Maybe this is a stupid question, but I am trying to find the math rule to prove that:

O(n^2.3) is less efficient than O(n^2logn)

`(n^2 logn) / n^2.3`

goes to zero as `n`

goes to infinity. (So `(n^2 logn)`

grows slower than `n^2.3`

.) You can prove this with L'Hôpital's Rule.

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